eqv?

(eqv? obj1 obj2)

The same predicate as eq? here: numbers of the same exactness and value are equivalent, so (eqv? 1.5 1.5) is #t, while (eqv? 2 2.0) is #f because the exactness differs. 0.0 and -0.0 are not eqv?; (eqv? +nan.0 +nan.0) is #t, which R7RS leaves unspecified (Gauche answers #f). Pairs, strings, vectors and procedures compare by identity; two string literals with the same text in one program may be the same object, which R7RS permits.